~~NOTOC~~ ====== Vector ====== A **vector** (specifically a **Euclidean vector**) is a geometric object with direction and magnitude. A vector is often represented as a directed line segment defined by an initial point $A$ with a terminal point $B$. Vector notation varies; a typical vector representation is $\vec{AB}$, symbolizing the vector from point $A$ to point $B$ (i.e. what is needed to "carry" point $A$ to point $B$). A vector may also be represented by a single symbol, e.g. $\vec{u}$. ===== Properties ===== ==== Addition/subtraction ==== Adding/subtracting vectors involves the addition/subtraction of each vector coordinate. As long as both vectors have matching dimensions, any two vectors can be added/subtracted to compute a resultant vector. $\vec{x} = \begin{bmatrix}x_1 \\ x_2 \\ x_3 \end{bmatrix},$ $\vec{y} = \begin{bmatrix}y_1 \\ y_2 \\ y_3 \end{bmatrix}$ $\quad\vec{x} + \vec{y} = \begin{bmatrix}x_1 + y_1 \\ x_2 + y_2 \\ x_3 + y_3 \end{bmatrix}$ $\quad\vec{x} - \vec{y} = \begin{bmatrix}x_1 - y_1 \\ x_2 - y_2 \\ x_3 - y_3 \end{bmatrix}$ \\ \\ **(Ex. 1)** Solve $\vec{x} + \vec{y}$ \\ \\ $\vec{x} = \begin{bmatrix}5 \\ -3 \\ 7 \end{bmatrix},$ $\vec{y} = \begin{bmatrix}0 \\ 15 \\ -2 \end{bmatrix}$
**[Show Answer]** $\vec{x} + \vec{y} = \begin{bmatrix}5 + 0 \\ -3 + 15 \\ 7 + -2 \end{bmatrix} = \begin{bmatrix}5 \\ 12 \\ 5 \end{bmatrix}$
\\ \\ **(Ex. 2)** Solve $\vec{x} - \vec{y}$ \\ \\ $\vec{x} = \begin{bmatrix}-3 \\ 13 \\ 6 \end{bmatrix},$ $\vec{y} = \begin{bmatrix}-9 \\ -4 \\ 12 \end{bmatrix}$
**[Show Answer]** $\vec{x} - \vec{y} = \begin{bmatrix}-3 - -9 \\ 13 - -4 \\ 6 - 12 \end{bmatrix} = \begin{bmatrix}6 \\ 17 \\ -6 \end{bmatrix}$
==== Scaling ==== To scale a vector is to change magnitude without changing direction. A vector is scaled when multiplied by a positive real coefficient. $\displaystyle\{k \in \mathbb{R} \mkern9mu | \mkern9mu 0 < k < \infty\},$ $\quad\vec{x} = \begin{bmatrix}x_1 \\ x_2 \\ x_3 \end{bmatrix},$ $\quad k\vec{x} = \begin{bmatrix}kx_1 \\ kx_2 \\ kx_3 \end{bmatrix}$ \\ \\ **(Ex. 3)** Find a real value $k$ such that $||k * \vec{x}|| = 2.5$ \\ \\ $\vec{x} = \begin{bmatrix}3 \\ -4 \\ 0 \end{bmatrix}$
**[Show Answer]** $\displaystyle || \vec{x} || = \sqrt{3^2 + (-4)^2} = 5$\\ $\displaystyle 2.5/5 = 1/2, \quad \displaystyle k || \vec{x} || = \frac{1}{2} || \vec{x} || = 2.5$\\ $k = 1/2$
\\ \\ ==== Normalization ==== ==== Dot product ==== ==== Cross product ==== ==== See also ==== * [[article:eigen|Eigenvector]] * [[article:linear_algebra|Linear algebra]]